Question 78

Murad can do a piece of work in 33 hours. If he is joined by Joel who is 100% more efficient, in what time will they together finish the work?

Solution

Let total work to be done be 33 units.

Murad's efficiency = $$\frac{33}{33} = 1$$ units/hour

Joel's efficiency = $$1 + \frac{100}{100} \times 1 = 2$$ units/hour

=> Murad's and Joel's 1 day's work together = 1 + 2 = 3 units/hour

$$\therefore$$ Time taken by them together = $$\frac{33}{3} = 11$$ hours

=> Ans - (D)

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