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Question 77
A and B together do a job in 6.75 days and A could do the job in 9 days if he worked alone. How many days would B take to do the job if he worked alone?
Solution
Let total work = 27 units
A+B efficiency = 27/6.75 = 4
A's efficiency = 27/9 = 3
B's efficiency = 4-3 = 1
B alone can complete the work in 27/1 = 27 days
So the answer is option A.
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