By what least number should 1200 be multiplied so that it becomes a perfect square?
Prime factorization of 1200 = $$2^4\times3\times5^2$$
Now, to make it a perfect square, all the powers should be even, but clearly power of 3 is 1, which is odd.
Thus, least number that should be multiplied by 1200 so that it becomes a perfect square = 3
=> $$1200\times3=3600=(60)^2$$
=> Ans - (B)
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