Question 76

By what least number should 1200 be multiplied so that it becomes a perfect square?

Solution

Prime factorization of 1200 = $$2^4\times3\times5^2$$

Now, to make it a perfect square, all the powers should be even, but clearly power of 3 is 1, which is odd.

Thus, least number that should be multiplied by 1200 so that it becomes a perfect square = 3

=> $$1200\times3=3600=(60)^2$$

=> Ans - (B)

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