The full marks for a paper is 300. The break-up of the marks into theory (X), practical (Y) and project (Z), which are the three components of evaluation is 6 : 5 : 4. In order to pass one has to score at least 40%, 50% and 50% respectively in X, Y, Z and 60% in aggregate. The marks scored by four students A, B, C and D are shown in the given Bar Graph.

Who among the students could not pass ?

Full marks of x = $$\frac{6}{15}\times300= 120$$ and pass marks = $$120\times\frac{40}{100}=48$$

Full marks of y = $$\frac{5}{15}\times300= 100$$ and pass marks = $$100\times\frac{50}{100}= 50$$

Full marks of z = $$\frac{4}{15}\times300= 80$$ and pass marks = $$100\times\frac{50}{80}=40$$

Aggregate marks for pass = $$300\times\frac{60}{100}=180$$

The project marks(z) of B is less than passing marks as well as aggregate marks is also less than 60%.

The project marks(z) of D is also less than passing marks. 

Hence B and D could not pass.