The average of 1088 real numbers is zero. At most how many of them can be negative?
Average of 1088 real numbers = 0
Sum of 1088 real numbers = $$0\times1088=0$$
It may be possible that 1087 numbers are in negative and their sum be $$-x$$, then 1088th number must be in positive and their sum willl be $$+x$$
So, $$-x + x$$ = 0
Average =$$ \frac{0}{20}=0$$
So, 1087 numbers will be in negative.
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