'A' sells an article to 'B' at 12% profit. 'B' sells it to 'C' at 9% loss. If 'C' pays ₹15,288 for it, then at what price (in ₹) is the article sold by A?

Let the Cost price of article for A is x.

• A sells article to B at 12 % profit. 

i.e; Selling price of A = Cost price for B = $$x+\ \frac{12}{100}x=\frac{112x}{100}$$

• B sells to C at 9 % loss. 

i.e; Selling Price of B = Cost price for C = $$\frac{112x}{100}-\frac{9}{100}\times\ \frac{112x}{100}=\frac{10192x}{10000}$$

• Cost price for C = ₹15,288 

So, $$\frac{10192x}{10000}=15288$$

$$\therefore\ x=₹15000$$ = Cost price for A

Selling price of B = $$\frac{112}{100}\times\ 15000=₹16800$$

Hence, Option B is correct.