Question 74

A man on tour travels the first 360 km by train at 72 km/h, the next 160 km on a motorcycle at 12.80 km/h, and the last 200 km by bicycle at 16 km/h. Ignoring the buffer times between the different modes of travel, what is the average speed (in m/s)for his tour?

Solution

A man on tour travels the first 360 km by train at 72 km/h, the next 160 km on a motorcycle at 12.80 km/h, and the last 200 km by bicycle at 16 km/h.

Average speed = $$\frac{\left(360+160+200\right)}{\frac{360}{72}+\frac{160}{12.8}+\frac{200}{16}}$$

= $$\frac{720}{5+12.5+12.5}$$

= $$\frac{720}{30}$$

= 24 km/h

= $$24\times\frac{1000}{3600}$$

= 6.67 m/s

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