A grocer has a sale of ₹9,435, ₹9,927, ₹9,855, ₹9,230 and ₹9,562 for five consecutive months. How much sale (in ₹) must he have in the sixth month so that he gets an average sale of ₹9,500?
Let the sale of 6th month be x.
As we know,
$$\therefore\ Average\ =\ \frac{Sum\ of\ observation}{number\ of\ observation}$$
According to question,
$$\therefore\ 9500=\ \frac{9435+9927+9855+9230+9562}{6}$$
$$\therefore\ 9500\times6\ =\ 48009+x$$
$$\therefore\ x=57000-48009$$
$$\therefore\ x=8991$$
Hence, option C is correct.
Create a FREE account and get:
