Question 74

A grocer has a sale of ₹9,435, ₹9,927, ₹9,855, ₹9,230 and ₹9,562 for five consecutive months. How much sale (in ₹) must he have in the sixth month so that he gets an average sale of ₹9,500?

Solution

Let the sale of 6th month be x.

As we know,

$$\therefore\ Average\ =\ \frac{Sum\ of\ observation}{number\ of\ observation}$$

According to question,

$$\therefore\ 9500=\ \frac{9435+9927+9855+9230+9562}{6}$$

$$\therefore\ 9500\times6\ =\ 48009+x$$

$$\therefore\ x=57000-48009$$

$$\therefore\ x=8991$$

Hence, option C is correct.

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