Question 73

If a 10-digit number 7220x558y2 is divisible by 88, then the value of (5x + 5y) can be :

Solution

We have : 7220x558y2 divisible by 88
Now 88 = (8)(11)
So the number is divisible by both 8 and 11
Now for a number to be divisible by 8 , the last three digits should be divisible by 8 
and we know that 832 and 872 mod 8 =0 so y can be 3 or 7
Now taking y =7
we get 7220x55872
Now the divisibility of 11 says the |sum of digits at even positions - sum of digits at odd positions| mod 11 =0
so we get |17-21-x | mod 11 =0
we get x =7
Therefore 5x+5y =70
Taking y =3
we get 7220x55832
we get 17-17-x mod 11 =0
x=0
Therefore 5x+5y =15
so from options we can say 5x+5y can be 15


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