Question 72
The Table presents the amount of milk (in litres) sold by two milkmen in eight days.
The total amount of milk (in litres) sold by milkman 2 in all 8 days is what percent(correct to one decimal place) more than the total amount of milk sold by milkman 1 in the first six days?
Solution
The total amount of milk sold by milkman 2 in all 8 days = 31+32+43+41+49+59+62+69
= 386
the total amount of milk sold by milkman 1 in the first six days = 28+34+38+37+53+58
= 248
percentage more = $$\frac{\left(386-248\right)}{248}\times100$$
= $$\frac{138}{248}\times100$$
= 55.64%
= 55.6% approx.
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