Question 72

The Table presents the amount of milk (in litres) sold by two milkmen in eight days.

The total amount of milk (in litres) sold by milkman 2 in all 8 days is what percent(correct to one decimal place) more than the total amount of milk sold by milkman 1 in the first six days?

Solution

The total amount of milk sold by milkman 2 in all 8 days = 31+32+43+41+49+59+62+69

= 386

the total amount of milk sold by milkman 1 in the first six days = 28+34+38+37+53+58

= 248

percentage more = $$\frac{\left(386-248\right)}{248}\times100$$

= $$\frac{138}{248}\times100$$

= 55.64%

= 55.6% approx.

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: