Question 72

The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.

The marks obtained by S5 is how much percent more than the average marks of the students (correct to two decimal)?

Solution

number of employees in year S5 = 99

avg1 = $$\frac{88+92+87+94+99+97+86+85+100+91 }{10}$$ = 91.9

S5 is how much percent more than the average marks of the students

= $$\frac{ 99-91.9}{91.9}100$$ = 7.73%


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