Question 72
The Bar graph given below presents the marks (out of 100) obtained by 10 students in a subject.
The marks obtained by S5 is how much percent more than the average marks of the students (correct to two decimal)?
Solution
number of employees in year S5 = 99
avg1 = $$\frac{88+92+87+94+99+97+86+85+100+91 }{10}$$ = 91.9
S5 is how much percent more than the average marks of the students
= $$\frac{ 99-91.9}{91.9}100$$ =Â 7.73%
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