Given, 10-digit number 1230x558y2 is divisible by 88 then the number must be divisible by 11
If it is divisible by 11 then,
Sum of digits at even place - Sum of digits at odd place = 0 or multiple of 11
$$=$$>Â (2+0+5+8+2)-(1+3+x+5+y) = 0 or multiple of 11
$$=$$>Â 17-9-(x+y) = 0 or multiple of 11
$$=$$> Â 8-(x+y) = 0 or multiple of 11
If 8-(x+y) = multiple of 11 then x+y is negative which is not a possible case
$$=$$>Â 8-(x+y) = 0
$$=$$> Â Â x+y = 8
$$\therefore\ $$5x+5y = 5(x+y) = 5(8) = 40
Hence, the correct answer is Option A
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