Question 71

Two students appeared for an examination. One of them secured 20 marks more than the other and his marks were 55% of the sum of their marks. The marks obtained by them are

Solution

Let marks scored by 1st student = $$x$$

=> Marks scored by another student = $$(x + 20)$$

According to question, => $$(x + 20) = \frac{55}{100} \times (x + x + 20)$$

=> $$x + 20 = \frac{11}{10} \times (x + 10)$$

=> $$10x + 200 = 11x + 110$$

=> $$11x - 10x = 200 - 110 = 90$$

=> $$x = 90$$

$$\therefore$$ Marks scored by other student = 90 + 20 = 110

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