Two equal sums were lent on simple interest at 6% and 10% per annum respectively. The first sum was recovered two years later than the second sum and the amount in each case was ₹1105. What was the sum (in ₹) lent in each scheme?

Let the sum lent in each scheme = P

Let the sum at 6% and 10% simple interest was recovered after 't+2' years and 't' years respectively.

Amount obtained from simple interest at 6% = P + $$\frac{P\times(t+2)\times6}{100}$$

1105 = P + $$\frac{P\times(t+2)\times6}{100}$$

1105 - P = $$\frac{P\times(t+2)\times6}{100}$$.......(1)

Amount obtained from simple interest at 10% = P + $$\frac{P\times t\times10}{100}$$

1105 = P + $$\frac{P\times t\times10}{100}$$

1105 - P = $$\frac{P\times t\times10}{100}$$........(2)

From (1) and (2),

$$\frac{P\times(t+2)\times6}{100}$$ = $$\frac{P\times t\times10}{100}$$

6t + 12 = 10t

t = 3

Substituting t = 3 in equation (2), we get P = 850

The sum lent in each scheme = ₹850

Hence, the correct answer is Option B