Question 71

The given Bar Graph presents the sale (in 1000 kg) of a particular brand of tea by three outlets, A, B and C during the months Jan, Feb, Mar and Apr, 2018.

By how much quantity is the average sale per month from B more or less than that from C ?

Solution

Average sale per month of B = $$\frac{\left(9000+7000+9000+11000\right)}{4}=9000$$

Average sale per month of C = $$\frac{\left(10000+5000+8000+9000\right)}{4}=8000$$

So, B is more than C by 1000 kg.

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: