Sign in
Please select an account to continue using cracku.in
↓ →
The given Bar Graph presents the Demand and Production of motorcycles of five companies(in lakhs).
The average Production of motorcycles of companies B, C and E taken together is what percent less than the Demand of motorcycles of D ?
The total number of production of motorcycles from companies B, C and E $$= 90+135+120 =345$$
So, Average number of production of motorcycles from companies B, C and E$$=\dfrac{345}{3} = 115$$
Demand of motorcycles from company D$$=125$$
Hence, the required percentage $$=\dfrac{(125-115)\times100}{125} =\dfrac{10 \times100}{125}$$
$$=\dfrac{1000}{125}=8\%$$
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
