The area of a trapezium is 100 $$cm^{2}$$. If the distance between the parallel sides of the trapezium is 10 cm, then what is the sum of the lengths of the two parallel sides?
area of a trapezium =Â $$\frac{1}{2}\times\ sum\ of\ the\ lengths\ of\ the\ two\ parallel\ sides\times dis\tan ce\ between\ the\ parallel\ sides$$
$$100=\frac{1}{2}\times\ sum\ of\ the\ lengths\ of\ the\ two\ parallel\ sides\times\ 10$$
$$10=\frac{1}{2}\times\ sum\ of\ the\ lengths\ of\ the\ two\ parallel\ sides$$the sum of the lengths of the two parallel sides of trapezium = 20 cm
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