In the given figure, PQRS is a cyclic quadrilateral. What is the measure of the angle PQR if PQ is parallel to SR?

In the cyclic quadrilateral PQRS,

Sum of opposite angles = 180$$^{\circ\ }$$

$$=$$>  $$\angle$$SPQ + $$\angle$$SRQ = 180$$^{\circ\ }$$

$$=$$>  110$$^{\circ\ }$$ + $$\angle$$SRQ = 180$$^{\circ\ }$$

$$=$$>  $$\angle$$SRQ = 70$$^{\circ\ }$$

Given, PQ is parallel to SR

RQ is the transversal intersecting the parallel lines PQ and SR

Sum of the interior angles on the same side of the transversal is 180$$^{\circ\ }$$

$$=$$>  $$\angle$$SRQ + $$\angle$$PQR = 180$$^{\circ\ }$$

$$=$$>  70$$^{\circ\ }$$ + $$\angle$$PQR = 180$$^{\circ\ }$$

$$=$$>  $$\angle$$PQR = 110$$^{\circ\ }$$

Hence, the correct answer is Option A