If $$(x - 7)^3 + (2x + 8)^3 + (2x - 3)^3 = 3 (x — 7) (2x + 8) (2x — 3)$$, then what is the value of $$x$$ ?
Given, $$(x - 7)^3 + (2x + 8)^3 + (2x - 3)^3 = 3 (x — 7) (2x + 8) (2x — 3)$$
$$=$$> $$(x - 7)^3 + (2x + 8)^3 + (2x - 3)^3 - 3 (x — 7) (2x + 8) (2x — 3)=0$$
We know that if $$a^3+b^3+c^3-3abc=0$$ then $$a+b+c=0$$
$$=$$> $$\left(x-7\right)+\left(2x+8\right)+\left(2x-3\right)=0$$
$$=$$> $$5x-2=0$$
$$=$$> $$x=\frac{2}{5}$$
$$=$$> $$x=0.4$$
Hence, the correct option is Option B
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