A has thrice as much amount as that of B and B has 40% more amount than C. If the average of the amount of all three of them is Rs 1320, then what amount (in Rs) A has?
Let amount with C = $$Rs.$$Â $$100x$$
=> B's amount = $$100x+(\frac{40}{100}\times100x)=Rs.$$ $$140x$$
=> A's amount = $$3\times140x=Rs.$$ $$420x$$
Average amount with the three = $$\frac{(100x+140x+420x)}{3}=1320$$
=> $$\frac{660x}{3}=1320$$
=> $$220x=1320$$
=> $$x=\frac{1320}{220}=6$$
$$\therefore$$ Amount (in Rs.) that A has = $$420\times6=Rs.$$ $$2520$$
=> Ans - (B)
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