Question 69

What is the value of x in the following equation?
$$[900 \div (11 \times 12 \div 4 \times 3 - 98)^{2}] = x$$

Solution

[ $$900 ( \ \frac{\ 11\times\ 12\ \frac{\ 4\times\ 3} { }}{ }\ -\ 98 ) ^2 ]=x$$

[ $$900 ( \ \ \frac{\ 11\times\ 3\times\ 3 }{ } -\ 98\ ) ^2\ ] =x$$

[ $$900 ( \ \ \frac{\ 33\times\ 3 } { }-\ 98\ ) ^2\ ] =x$$

[ $$900 ( \ \ \frac{\ 99}{ }\ -\ 98 ) ^2\ ] =x$$

[ $$900\ \ \frac{\ 1}{ }\ \ ] =x$$

$$900\ \frac{\ 1}{ }=x$$
$$900\ =\ x$$

Hence the value of X is 900, so the correct option is A

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