Question 69

The length, breadth and height of a cuboid are 15 cm, 12 cm and 11 cm respectively. The length is decreased by $$6\frac{2}{3}\%$$, the breadth increased by $$8\frac{1}{3}\%$$, whereas the height is kept unchanged. What is the changein the total area of the four side faces (considering the rectangle contained by the length and breadth as the base) of the cuboid?

Solution

l = 15 , b = 12 , h = 11

Area of four sides = 2(lh + bh) = 2h(l +b) = 22(15 + 12) = 594

when dimensions are changed ,

New l = 14 , New b = 13

Area of four sides = 2(lh + bh) = 2h(l +b) = 22(14 + 13) = 594

There is no change in area of walls.

So, the answer would be option a)No change

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