The average salary of managers is x and the average salary of workers is y. The number of the managers is 15 times of the number of workers. What is average salary of managers and workers together?
Let number of workers = $$1$$, => Number of managers = $$15$$
=> Total salary of workers = $$y$$ and total salary of managers = $$15x$$
$$\therefore$$ Required average = $$\frac{15x+y}{15+1}$$
=Â $$\frac{(15x + y)}{16}$$
=> Ans - (A)
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