Question 69

In the triangle, If $$AB = AC$$ and $$\angle ABC = 72^\circ$$, then $$\angle BAC$$ is:

Solution

By triangle properties,

When AB = AC then $$\angleABC = \angleACB$$ so,

In$$\triangle$$ ABC,

$$\Rightarrow$$ $$ \angle ABC + \angle ACB + \angle BAC = 180^{0}$$

$$\Rightarrow \angle ABC + \angle ABC + \angle BAC = 180^{0}$$

$$\Rightarrow 72^{0} + 72^{0} + \angle BAC = 180^{0}$$

$$\Rightarrow \angle BAC = 180^{0} - 144^{0} = 36^{0}$$

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