Question 69

If the length of a side of the square is equal to that of the diameter of a circle, then the ratio of the area of the square and that of the circle is: ($$\pi = \frac{22}{7}$$)

Solution

Given,

Length of a side of the square is equal to that of the diameter of a circle.

L = D

R = $$\frac{D}{2}$$

D = 2R

L = 2R

Area of square = $$\left(L\right)^2$$

Area of circle = $$\pi\ R^2$$

Required Ratio = $$\frac{(2R)^2}{\pi\ \left(R\right)^2}$$

= $$\frac{4}{\pi}\ $$

= $$\frac{4\times\ 7}{\ 22}\ $$

= $$\frac{4\times\ 7}{\ 22}\ =14\ :\ 11$$

Hence, Option A is correct.

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