If the length of a side of the square is equal to that of the diameter of a circle, then the ratio of the area of the square and that of the circle is: ($$\pi = \frac{22}{7}$$)
Given,
Length of a side of the square is equal to that of the diameter of a circle.
L = DÂ
R =Â $$\frac{D}{2}$$
D = 2R
L = 2RÂ
Area of square = $$\left(L\right)^2$$Â
Area of circle =Â $$\pi\ R^2$$
Required Ratio =Â $$\frac{(2R)^2}{\pi\ \left(R\right)^2}$$
=Â $$\frac{4}{\pi}\ $$
=Â $$\frac{4\times\ 7}{\ 22}\ $$
=Â $$\frac{4\times\ 7}{\ 22}\ =14\ :\ 11$$
Hence, Option A is correct.Â
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