Question 69
Find the angular elevation of the sum when the shadow of a 15m long pole is $$\frac{15}{\sqrt{3}}$$ metres
Solution
We have :
Now AB is the pole
BC is the shadow
ACB is the angle of elevation of pole
we get Tan ACB = $$\frac{AB}{BC}$$ =$$\sqrt{\ 3}$$
We get ACB = 60
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