Question 69

Find the angular elevation of the sum when the shadow of a 15m long pole is $$\frac{15}{\sqrt{3}}$$ metres

Solution

We have : 

Now AB is the pole 
BC is the shadow 
ACB is the angle of elevation of pole
we get Tan ACB = $$\frac{AB}{BC}$$ =$$\sqrt{\ 3}$$
We get ACB = 60


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