A sum of money is distributed among A, B, C and in the ratio 5: 7: 11 : 15, respectively. If C gets ₹2,480 more than B, then the difference between the shares of B and is:

The four persons are $$A : B : C : D = 5 : 7 : 11 : 15$$.
Let the common multiplying factor be $$x$$. Then their individual shares are
  $$A = 5x,\; B = 7x,\; C = 11x,\; D = 15x$$.

C gets ₹2,480 more than B, so

$$C - B = 11x - 7x = 4x = 2480$$.

Solving for $$x$$:

$$x = \frac{2480}{4} = 620$$.

Now find B's and D's shares:

$$B = 7x = 7 \times 620 = 4340$$,  $$D = 15x = 15 \times 620 = 9300$$.

Difference between D and B:

$$D - B = 9300 - 4340 = 4960$$.

Hence, the required difference is ₹4,960.

Option D which is: ₹4,960