Question 69

A and B can do a piece of work in 12 days. A is one and a half times more efficient than B. In how many days does A complete the work independently?

Solution

A is one and a half times more efficient than B.

Let's assume the efficiency of B is 2y.

efficiency of A = $$1.5\times2y$$ = 3y

A and B can do a piece of work in 12 days.

Total work = $$12\times(3y+2y)$$

= $$12\times5y$$

= 60y

The number of days taken by A to complete the work independently = $$\frac{60y}{3y}$$

= 20 days

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