Question 69
A and B can do a piece of work in 12 days. A is one and a half times more efficient than B. In how many days does A complete the work independently?
Solution
A is one and a half times more efficient than B.
Let's assume the efficiency of B is 2y.
efficiency of A = $$1.5\times2y$$ = 3y
A and B can do a piece of work in 12 days.
Total work = $$12\times(3y+2y)$$
= $$12\times5y$$
= 60y
The number of days taken by A to complete the work independently = $$\frac{60y}{3y}$$
= 20 days
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