Solution
If $$(x - a)$$ is a factor of $$f(x)$$, then $$f(a) = 0$$
Now, $$(x - 2)$$ is factor of $$f(x) = (x^{2} - kx + 2)$$
Thus, putting $$x = 2$$
=> $$f(2) = (2^2 - 2k + 2) = 0$$
=> $$-2k = 0 - 4 - 2 = -6$$
=> $$k = \frac{-6}{-2} = 3$$
Get AI Help?
Create a FREE account and get:
- Download Maths Shortcuts PDF
- 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
