Solution
6 = $$2\times3\times1$$
7 = $$7\times1$$
8 = $$2\times2\times2\times1$$
The LCM of 6, 7 and 8 is 168.
The largest three-digit number is 999.
The required number should be completely divisible by 168 which is the LCM of 6, 7 and 8.
So when we will divide 999 by 168, then the remainder will be 159.
Hence the required number = 999-159
= 840
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
