Question 68

The average of four consecutive odd numbers is 8. If the next odd number is also considered, then what will be the new average of these five numbers?

Let's assume the four consecutive odd numbers are y, (y+2), (y+4) and (y+6).

The average of four consecutive odd numbers is 8.

$$\frac{y+(y+2)+(y+4)+(y+6)}{4}=8$$

$$y+(y+2)+(y+4)+(y+6)=32$$

4y+12 = 32
4y = 32-12
4y = 20

y = 5

If the next odd number is also considered, then the new average of these five numbers = $$\frac{y+(y+2)+(y+4)+(y+6)+(y+8)}{5}$$

= $$\frac{5+(5+2)+(5+4)+(5+6)+(5+8)}{5}$$

= $$\frac{5+7+9+11+13}{5}$$

= $$\frac{45}{5}$$

= 9

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