A tent is to be built in the form of a cylinder of radius 5 m surmounted by a cone of the same radius. If the height of the cylindrical part is 6 m and slant height of the conical part is 10 m, how much canvas will be required to build the tent? Allow 20% extra canvas for folding and stitching. (Take π = 22/7)

Radius of cone = Radius of cylinder = r = 5 m

Height of cylinder = h = 6 m

Slant height of cone = l = 10 m

Canvas required = Curved surface area of cylinder + Curved surface area of cone

= $$2 \pi r h + \pi r l = (\pi r) (2 h + l)$$

= $$(\frac{22}{7} \times 5) (2 \times 6 + 10)$$

= $$\frac{110}{7} \times 22 = 345.71$$ $$m^2$$

Also, 20% extra canvas is required for folding and stitching

$$\therefore$$ Total canvas required = $$\frac{120}{100} \times 345.71$$

= $$1.2 \times 345.71 \approx 414.86$$ $$m^2$$

=> Ans - (B)