Question 67

Three medians AD, BE and CF of ∆ABC intersect at G; Area of ∆ABC is 36 sq cm. Then the area of ∆CGE is

Solution

The medians of a triangle divide into 6 triangles of equal areas.

=> $$ar(\triangle AFG)$$ = $$ar(\triangle BFG)$$ = $$ar(\triangle BDG)$$ = $$ar(\triangle CGD)$$ = $$ar(\triangle CGE)$$ = $$ar(\triangle AGE)$$

Thus, $$ar(\triangle ABC)$$ = $$6 \times ar(\triangle CGE)$$

=> $$ar(\triangle CGE)$$ = $$\frac{1}{6} \times 36=6$$ $$cm^2$$

=> Ans - (B)

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