In a circle centred at O, AB is a chord and C is any point on AB, such that OC is perpendicular to AB. If the length of the chord is 16 cm and OC = 6 cm, the radius of circle is:

Let the radius of the circle = r

Given, AB = 16 cm, OC = 6 cm

OC is perpendicular to the chord AB.

In a circle, perpendicular from centre of the circle to the chord bisects the chord.

$$\Rightarrow$$ AC = BC = 8 cm

In $$\triangle$$OAC,

AC$$^2$$ + OC$$^2$$ = OA$$^2$$

$$\Rightarrow$$ 8$$^2$$ + 6$$^2$$ = r$$^2$$

$$\Rightarrow$$ 64 + 36 = r$$^2$$

$$\Rightarrow$$ r$$^2$$ = 100

$$\Rightarrow$$  r = 10 cm

$$\therefore\ $$Radius of the circle = 10 cm

Hence, the correct answer is Option C