If an equilateral triangle has side 12 cm, then what is the difference (in cm) between the circumradius and inradius?
Side of equilateral triangle = $$a=12$$ cm
=> Circumradius of equilateral triangle = $$R=\frac{a}{\sqrt3}$$ cm and inradius = $$r=\frac{a}{2\sqrt3}$$ cm
$$\therefore$$Â Difference (in cm) between the circumradius and inradius
= $$\frac{a}{\sqrt3}-\frac{a}{2\sqrt3}=\frac{a}{2\sqrt3}$$
= $$\frac{12}{2\sqrt3}=\frac{6}{\sqrt3}$$
= $$2\sqrt3$$ cm
=> Ans - (C)
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