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Question 67
A hollow iron pipe is 10 cm long and its external diameter is 18 cm. If the thickness of the pipe is 2 cm and iron weighs 8.5 g/cm$$^3$$, then the weight of the pipe from the following is closest to:
Solution
External radius of the pipe = 9 cm
Internal radius of the pipe = 9-2 = 7cm
Volume of the pipe = $$\pi \times (9^2 - 7^2) \times 10 = 1005.71 cm^3$$
Weight of the pipe per $$cm^3 = 8.5 gm$$
Then, Total weight = 1005.71*8.5 = 8548 gm = 8.54 kg
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