Two cars travel from city A to city B at a speed of 30 and 44 km/hr respectively. If one car takes 3.5 hours lesser time than the other car for the journey, then the distance between City A and City B is

Let the distance between City A and City B = $$d$$ km

Speed of first car = 30 km/hr and speed of second car = 44 km/hr

Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 3.5)$$ hrs

Using, speed = distance/time for first car :

=> $$\frac{d}{t} = 30$$

=> $$d = 30t$$ --------------(i)

For second car, => $$\frac{d}{t - 3.5} = 44$$

Substituting value of $$d$$ from equation (i), we get :

=> $$30t = 44t - 154$$

=> $$44t - 30t = 14t = 154$$

=> $$t = \frac{154}{14} = 11$$ hrs

From equation (i), => $$d = 30 \times 11 = 330$$ km

=> Ans - (A)