The vertices of a triangle are A(−1, 3), B(−2, 2) and C(3, −1). A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is:

A

$$x + y + (2 - \sqrt{2}) = 0$$

B

$$-x + y - (2 - \sqrt{2}) = 0$$

C

$$x + y - (2 - \sqrt{2}) = 0$$

D

$$x - y - (2 + \sqrt{2}) = 0$$