Question 66
If the curved surface area of a sphere increased by 44%, then by what percentage would its volume increase?
Solution
Curved surface area of a sphere=$$4\pi r^{2}$$
New curved surface area=1.44*$$4\pi r^{2}$$
New curved surface area=$$4\pi (1.2r)^{2}$$
New radius=1.2r
Volume of the sphere=$$(4/3)\pi r^{3}$$
Volume of sphere with new radidus=$$(4/3)\pi (1.2r)^{3}$$
=1.728$$(4/3)\pi r^{3}$$
Change=((1.728-1)/1)*100
=0.728*100
=72.8%
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