Question 66

If the adjacent sides of a rectangle, whose perimeter is 66 m, are in the ratio 5 : 6, then what will be the area of the rectangle?

Solution

If the adjacent sides of a rectangle, whose perimeter is 66 m, are in the ratio 5 : 6.

Let's assume the adjacent sides of a rectangle is 5y and 6y.

perimeter of a rectangle = 2(sum of adjacent sides of a rectangle)

66 = 2(5y+6y)

33 = (5y+6y)

11y = 33

y = 3

Area of the rectangle = product of adjacent sides of a rectangle

= $$5y\times\ 6y$$

= $$30y^2$$

= $$30\times3^2$$

= $$30\times9$$

= 270 $$m^2$$

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