Question 66

An alloy X contains by weight copper and tin in the ration 7 : 3 and alloy Y contain copper and tin in the ratio 3 : 2. X and Y are taken in the ratio 4 : 1 and melted to form alloy Z. The percentage of copper in alloy Z is:

Solution

Quantity of copper in 10 units of X = 7 units, similarly quantity of copper in 10 units of Y = 6

To form Z, we need X : Y = 4 : 1,

Thus, 40 units of X contains 28 units copper and 10 units of Y contains 6 units copper

Thus, in total of 50 units, copper is 34 units, required % = $$\frac{34}{50}\times100=68\%$$

=> Ans - (D)

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