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A rectangular room has an area of 60 $$m^{2}$$ and perimeter of 34 m.The length of the diagonal of the rectangular room is same as the side of a square.The area of the square (in $$m^{2}$$)
Let the length and breadth of the rectangular room is $$l\ and\ b$$
Given,
Area = 60 $$m^2$$
We know, Area = $$l\times\ b$$
i.e, $$l\times\ b\ =\ 60$$
Perimeter = $$2\left(l+b\right)\ $$ = 34 (given)
i.e $$l+b\ =\ 17$$
By solving, we get l = 12 cm and b = 5 cm
Diagonal of a rectangle = $$l^2+b^2\ =\ d^2$$
$$\therefore\ d\ =\ \sqrt{\ 144+25}=13$$
According to question,
Diagonal of the rectangular room is same as the side of a square
i.e side of square = 13
Area = square = $$\left(side\right)^2$$
= $$\left(13\right)^2$$ = 169
Option A is correct.
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