Sign in
Please select an account to continue using cracku.in
↓ →
A pipe can fill a cistern in 20 minutes where as the cistern when full can be emptied by a leak in 28 minutes. When both are opened, The time taken to fill the cistern is:
Time taken to fill the cistern full when both are open is (1/x)=(1/20)-(1/28)
(1/x)=(7-5)/140
x=70 min
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation