Question 66

A pipe can fill a cistern in 20 minutes where as the cistern when full can be emptied by a leak in 28 minutes. When both are opened, The time taken to fill the cistern is:

Time taken to fill the cistern full when both are open is (1/x)=(1/20)-(1/28)
(1/x)=(7-5)/140
x=70 min

Was this solution helpful?

Get AI Help

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

Join CAT 2026 course by 5-Time CAT 100%iler

Start your IIM journey with the right preparation and crack CAT 2026.

Ask AI