The sides AB and AC of a $$\triangle$$ABC are extended to P and Q respectively. If the bisectors of $$\angle$$PBC and $$\angle$$QCB intersect at O, and $$\angle$$A = $$92^\circ$$, then  $$\angle$$BOC is equal to:

A

$$46^\circ$$

B

$$42^\circ$$

C

$$88^\circ$$

D

$$44^\circ$$