Question 65

A man divides ₹1,100 among three kids in the ratio $$\frac{1}{2} : \frac{2}{5} : \frac{3}{4}$$. What is the share of the kid who got the maximum share?

Solution

A man divides ₹1,100 among three kids in the ratio $$\frac{1}{2} : \frac{2}{5} : \frac{3}{4}$$.

ratio = $$\frac{10}{20}:\frac{8}{20}:\frac{15}{20}$$

ratio = 10 : 8 : 15

Let's assume the share of kids is 10y, 8y and 15y.

Share of the kid who got the maximum share = $$\frac{1100}{10y+8y+15y}\times15y$$

= $$\frac{1100}{33y}\times15y$$

= $$100\times5$$

= ₹500

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