A dealer sells a radio at a gain of 10%. If he had bought it at 10% less and sold it for 132 less, he would have still gained 10%. The cost price of the radio is

Let cost price of the radio = Rs. $$100x$$

Profit % = 10%

=> Selling price = $$\frac{10}{100}\times100x=Rs.$$ $$110x$$

Now, new cost price = $$C'=100x-(\frac{10}{100}\times100x)=Rs.$$ $$90x$$

Similarly, new selling price = $$S'=Rs.$$ $$(110x-132)$$

=> Profit % = $$\frac{(S'-C')}{C'}\times100$$

=> $$\frac{(110x-132)-90x}{90x}\times100=10$$

=> $$\frac{20x-132}{90x}=\frac{10}{100}$$

=> $$\frac{20x-132}{9x}=1$$

=> $$20x-132=9x$$

=> $$20x-9x=11x=132$$

=> $$x=\frac{132}{11}=12$$

$$\therefore$$ Cost price = $$100\times12=Rs.$$ $$1,200$$

=> Ans - (B)