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Solution :
We need to find remainder when
$$7^{2022}+3^{2022}$$
is divided by $$5$$.
Now,
$$7 \equiv 2 \pmod 5$$
Therefore,
$$7^{2022} \equiv 2^{2022} \pmod 5$$
Also,
Powers of $$2$$ modulo $$5$$ repeat every 4 :
$$2^1 \equiv 2$$
$$2^2 \equiv 4$$
$$2^3 \equiv 3$$
$$2^4 \equiv 1 \pmod 5$$
Since,
$$2022 \equiv 2 \pmod 4$$
therefore,
$$2^{2022} \equiv 2^2 \equiv 4 \pmod 5$$
Now for $$3^{2022}$$ :
Powers of $$3$$ modulo $$5$$ also repeat every 4 :
$$3^1 \equiv 3$$
$$3^2 \equiv 4$$
$$3^3 \equiv 2$$
$$3^4 \equiv 1 \pmod 5$$
Again,
$$2022 \equiv 2 \pmod 4$$
Hence,
$$3^{2022} \equiv 3^2 \equiv 4 \pmod 5$$
Therefore,
$$7^{2022}+3^{2022} \equiv 4+4$$
$$\equiv 8$$
$$\equiv 3 \pmod 5$$
Final Answer :
$$3$$
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