Seven years ago, the average age of A, B and C was 51 years. If A is 3 years older than B and B is 3 years older then C then the present ages of A, B and C are ( in year)
Let C's present age = $$x$$ years
=> B's present age = $$(x+3)$$ years
=> A's present age = $$(x+6)$$ years
Average age 7 years ago = 51
=> $$\frac{(x-7)+(x+3-7)+(x+6-7)}{3}=51$$
=> $$(x-7)+(x-4)+(x-1)=51 \times 3=153$$
=> $$3x-12=153$$
=> $$3x=153+12=165$$
=> $$x=\frac{165}{3}=55$$ years
$$\therefore$$ A's age = $$55+6=61$$ years
B's age = $$55+3=58$$ years
C's age = $$55$$ years
=> Ans - (A)
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