Question 64

Seven years ago, the average age of A, B and C was 51 years. If A is 3 years older than B and B is 3 years older then C then the present ages of A, B and C are ( in year)

Solution

Let C's present age = $$x$$ years

=> B's present age = $$(x+3)$$ years

=> A's present age = $$(x+6)$$ years

Average age 7 years ago = 51

=> $$\frac{(x-7)+(x+3-7)+(x+6-7)}{3}=51$$

=> $$(x-7)+(x-4)+(x-1)=51 \times 3=153$$

=> $$3x-12=153$$

=> $$3x=153+12=165$$

=> $$x=\frac{165}{3}=55$$ years

$$\therefore$$ A's age = $$55+6=61$$ years

B's age = $$55+3=58$$ years

C's age = $$55$$ years

=> Ans - (A)

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