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Let G be the geometric mean of two positive numbers a and b, and M be the arithmetic mean of $$\frac{1}{a}$$ and $$\frac{1}{b}$$. If $$\frac{1}{M}$$ : G is 4 : 5, then a : b can be:
We are given two positive numbers $$a$$ and $$b$$. The geometric mean $$G$$ of $$a$$ and $$b$$ is defined as $$G = \sqrt{ab}$$. The arithmetic mean $$M$$ of $$\frac{1}{a}$$ and $$\frac{1}{b}$$ is given by $$M = \frac{\frac{1}{a} + \frac{1}{b}}{2}$$. Simplifying $$M$$, we get:
$$M = \frac{\frac{1}{a} + \frac{1}{b}}{2} = \frac{\frac{b + a}{ab}}{2} = \frac{a + b}{2ab}.$$
The problem states that $$\frac{1}{M} : G = 4 : 5$$, which means the ratio of $$\frac{1}{M}$$ to $$G$$ is 4 to 5. This can be written as:
$$\frac{\frac{1}{M}}{G} = \frac{4}{5} \quad \Rightarrow \quad \frac{1}{M \cdot G} = \frac{4}{5} \quad \Rightarrow \quad M \cdot G = \frac{5}{4}.$$
Substituting the expressions for $$M$$ and $$G$$, we have:
$$\left( \frac{a + b}{2ab} \right) \cdot \sqrt{ab} = \frac{5}{4}.$$
Simplify the left side:
$$\frac{a + b}{2ab} \cdot \sqrt{ab} = \frac{a + b}{2 \sqrt{ab} \cdot \sqrt{ab}} \cdot \sqrt{ab} = \frac{a + b}{2 \sqrt{ab}}.$$
Note that $$\sqrt{ab} = \sqrt{a} \sqrt{b}$$, so:
$$\frac{a + b}{2 \sqrt{ab}} = \frac{a + b}{2 \sqrt{a} \sqrt{b}}.$$
Set $$k = \sqrt{\frac{a}{b}}$$. This implies $$k^2 = \frac{a}{b}$$, so $$a = k^2 b$$. Substitute this into the equation:
$$\frac{k^2 b + b}{2 \sqrt{(k^2 b) \cdot b}} = \frac{b(k^2 + 1)}{2 \sqrt{k^2 b^2}} = \frac{b(k^2 + 1)}{2 \cdot k b} = \frac{k^2 + 1}{2k}.$$
We now have:
$$\frac{k^2 + 1}{2k} = \frac{5}{4}.$$
Solve for $$k$$:
Multiply both sides by $$2k$$:
$$k^2 + 1 = \frac{5}{4} \cdot 2k = \frac{10k}{4} = \frac{5k}{2}.$$
Multiply both sides by 2 to eliminate the denominator:
$$2(k^2 + 1) = 5k \quad \Rightarrow \quad 2k^2 + 2 = 5k \quad \Rightarrow \quad 2k^2 - 5k + 2 = 0.$$
Solve this quadratic equation using the quadratic formula:
$$k = \frac{5 \pm \sqrt{(-5)^2 - 4 \cdot 2 \cdot 2}}{2 \cdot 2} = \frac{5 \pm \sqrt{25 - 16}}{4} = \frac{5 \pm \sqrt{9}}{4} = \frac{5 \pm 3}{4}.$$
This gives two solutions:
$$k = \frac{5 + 3}{4} = \frac{8}{4} = 2 \quad \text{and} \quad k = \frac{5 - 3}{4} = \frac{2}{4} = \frac{1}{2}.$$
Recall that $$k = \sqrt{\frac{a}{b}}$$, so:
Now, check the options:
The ratio $$a : b = 1 : 4$$ (from $$k = \frac{1}{2}$$) corresponds to option A. The ratio $$4 : 1$$ is not listed in the options.
Verify $$a : b = 1 : 4$$:
Let $$a = 1$$, $$b = 4$$. Then:
$$G = \sqrt{1 \cdot 4} = \sqrt{4} = 2,$$
$$M = \frac{\frac{1}{1} + \frac{1}{4}}{2} = \frac{1 + 0.25}{2} = \frac{1.25}{2} = 0.625,$$
$$\frac{1}{M} = \frac{1}{0.625} = 1.6,$$
Ratio $$\frac{1}{M} : G = 1.6 : 2 = 1.6 \div 2 = 0.8 = \frac{4}{5}$$, which matches $$4 : 5$$.
Other options do not satisfy:
Thus, $$a : b = 1 : 4$$ is the only ratio from the options that satisfies the condition.
Hence, the correct answer is Option A.
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