Let $$a_1, a_2, a_3, \ldots$$ be an A.P, such that $$\frac{a_1 + a_2 + \ldots + a_p}{a_1 + a_2 + a_3 + \ldots + a_q} = \frac{p^3}{q^3}$$; $$p \neq q$$. Then $$\frac{a_6}{a_{21}}$$ is equal to:

A

$$\frac{41}{11}$$

B

$$\frac{31}{121}$$

C

$$\frac{11}{41}$$

D

$$\frac{121}{1681}$$